Is there a stop to Internet Backgammon cheaters?

I tend to agree with most of your post (Shackle).

 

When I argued that there was cheating, I was only referring to the stall bug used, ie: opponent moves then rescinds move, does this a few times then stops; the next thing that happens is you are told that you are delaying your move and are eventually timed out.

 

I doubt anyone playing on msn has not come across this, and we will all agree that it is cheating, and I just wanted to know if there is a way around this.

 

WIth regards to the dice: there is no doubt that they are not random, and in some way react to what is needed, but I doubt the opponent can fix them. I have frequently lost 12 on the trot, and sometimes won 12 on the trot.  When on your side you frequently throw the perfect throw needed, and vica versa when on losing streak.

 

My only disagreement with Mr Shackle is saying odds on any paritcular throw are 18-1. Obviously I agree they are not 36-1, that is obvious, but the correct odds are 21-1, as there are 21 different thriw combinations. Look at the table below. I may be incorrect, and please tell me if I have missed something, but I don't think so. I do remember when I first started playing Backgammon (30 years ago) reading a book, and they commented on the 36-1 myth, and used the table below to explain the 21-1 odds

 

1-1     2-2      3-3     4-4     5-5     6-6

2-1     2-3      3-4     4-5     5-6

3-1     2-4      3-5     4-6

4-1     2-5      3-6  

5-1     2-6 

5-1    

 

6  +     5    +    4    +    3    +   2    +   1      =    21 

This is gobble-de-gook.  You must include the TOTAL event space, not a partial, when calculating probability.  The book you read was wrong if it told you to use 21 as the denominator of probability calculations.  This partial list is valid only to describe the possible rolls in backgammon, but not to be used in calculating probability.

Here are some an examples:

All events:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Rolling a six:

(1,6) (2,6) (3,6) (4,6) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

That is 11/36 or 30.55%

Rolling 2 fours

(4,4)

That is 1/36

Rolling a four and a two

(4,2) (2,4)

That is 2/36 or 1/18

Rolling 2 fours or (a four and a two)

(4,4) (4,2) (2,4)

That is 3/36 or 1/12

Be careful not to espouse erroneous information and  visit..

http://gwydir.demon.co.uk/jo/probability/calcdice.htm

Quite clearly as we are talking about backgammon, I was talking about the odds on a throw, which is 21-1.

Do you need advice on the Emglish language?

Here is how they do it:

How to Cheat at Internet Backgammon

eHow Hobbies, Games & Toys Editor

This article was created by a professional writer and edited by experienced copy editors, both qualified members of the Demand Media Studios community. All articles go through an editorial process that includes subject matter guidelines, plagiarism review, fact-checking, and other steps in an effort to provide reliable information.

By an eHow Contributor

It seems that cheating at Internet backgammon would not be possible. Many times, online games have a predetermined outcome: One player rolls certain numbers and then plays predictable moves that cause them to win or lose. It seems that this is cheating, but neither player has any control over this. There is, however, a free program you can download that will help you truly cheat at Internet backgammon.

Related Searches:

Instructions

1. • 1

Download GNU Backgammon to your computer. This software analyzes possible moves and advises you of how to move your game pieces after you roll the dice. When you play every move the software tells you, it can help you win 70 to 85 percent of the time. - 2

Set up your software. Choose the options to play manually, that way you can change dice results and keep up with the game, as you play online. - 3

Create an account at an online backgammon site. Play a few rounds to see how the site functions. - 4

Start a backgammon game with a live player (or a computer, but preferably a live player). Adjust the software so you play the exactly as your live game and follow every move the analyzer suggests.

Read more: How to Cheat at Internet Backgammon | eHow.com http://www.ehow.com/how_4430301_cheat-internet-backgammon.html#ixzz1jC9yBT00

Ok, I'm starting to get out of my depth. Comprehending cheating in a game? Yes.

Backgammon? No.

I understand the maths of what you're saying, though. Just not how it relates to the game.

I tend to agree with most of your post (Shackle).

 

When I argued that there was cheating, I was only referring to the stall bug used, ie: opponent moves then rescinds move, does this a few times then stops; the next thing that happens is you are told that you are delaying your move and are eventually timed out.

 

I doubt anyone playing on msn has not come across this, and we will all agree that it is cheating, and I just wanted to know if there is a way around this.

 

WIth regards to the dice: there is no doubt that they are not random, and in some way react to what is needed, but I doubt the opponent can fix them. I have frequently lost 12 on the trot, and sometimes won 12 on the trot.  When on your side you frequently throw the perfect throw needed, and vica versa when on losing streak.

 

My only disagreement with Mr Shackle is saying odds on any paritcular throw are 18-1. Obviously I agree they are not 36-1, that is obvious, but the correct odds are 21-1, as there are 21 different thriw combinations. Look at the table below. I may be incorrect, and please tell me if I have missed something, but I don't think so. I do remember when I first started playing Backgammon (30 years ago) reading a book, and they commented on the 36-1 myth, and used the table below to explain the 21-1 odds

 

1-1     2-2      3-3     4-4     5-5     6-6

2-1     2-3      3-4     4-5     5-6

3-1     2-4      3-5     4-6

4-1     2-5      3-6  

5-1     2-6 

5-1    

 

6  +     5    +    4    +    3    +   2    +   1      =    21 

This is gobble-de-gook.  You must include the TOTAL event space, not a partial, when calculating probability.  The book you read was wrong if it told you to use 21 as the denominator of probability calculations.  This partial list is valid only to describe the possible rolls in backgammon, but not to be used in calculating probability.

Here are some an examples:

All events:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Rolling a six:

(1,6) (2,6) (3,6) (4,6) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

That is 11/36 or 30.55%

Rolling 2 fours

(4,4)

That is 1/36

Rolling a four and a two

(4,2) (2,4)

That is 2/36 or 1/18

Rolling 2 fours or (a four and a two)

(4,4) (4,2) (2,4)

That is 3/36 or 1/12

Be careful not to espouse erroneous information and  visit..

http://gwydir.demon.co.uk/jo/probability/calcdice.htm