A cross-platform toolchain for developing, building, running, and publishing .NET applications.
Hi @RLWA32
There is an MSBuild property that directly contains the path to the final single-file binary. You can use the $(PublishedSingleFilePath) property.
I have tested this and it works as expected. This property is populated during the Publish target specifically when creating a single-file bundle.
Because this property is created during the publish process, it will be empty if you define your <ItemGroup> at the top level of your project. You need to move your <ItemGroup> inside your target so MSBuild evaluates it after the publish process is complete and the property has a value.
Here is a general example of how to use it for a copy task:
<!-- Define the target to run after publish -->
<Target Name="MyPostPublishCopy" AfterTargets="Publish">
<!-- The ItemGroup must be inside the target to get the populated value -->
<ItemGroup>
<MySourceFile Include="$(PublishedSingleFilePath)" />
<MyDestFolder Include="C:\MyDestinationFolder\" />
</ItemGroup>
<Copy SkipUnchangedFiles="true"
SourceFiles="@(MySourceFile)"
DestinationFolder="@(MyDestFolder)" />
</Target>
By doing this, you will dynamically get the exact path and filename of the single-file application, regardless of the operating system or runtime identifier.
For more information on single-file deployments, you can refer to the official documentation on creating a single file for application deployment.If you found my response helpful or informative, I would greatly appreciate it if you could follow this guidance or provide feedback.
Thank you.