COUNTIF on cell color

Anonymous
2010-11-01T12:09:13+00:00

Hello,

Within Excel, I have a matrix of programs horizontally and accounts vertically and I have evaluated the performance of each intersection of the maxtrix with red (has concerning issues), yellow (has some issues), and green (no issues). At the bottom of my matrix, I'd like to use a COUNTIF formula to count the number of cells that are red, yellow, and green. What's the best way to COUNTIF on cell color? If needed, I can create a separate matrix that identifies the cell color by number (red,green,blue combination) and then do a lookup on that matrix.

Thanks,

Scott

Microsoft 365 and Office | Excel | For home | Windows

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Anonymous
2010-11-01T12:16:18+00:00

Hi,

Excel has no native way of doing this so we must create a UDF to do it. ALT+F11 to open vb editor, right click 'ThisWorkbook' and insert module and paste the code below in. Close VB editor.

Back on the worksheet call with

=Countcolour($A$1:$J$1,K1)

Where:-

A1:J1 is the range you want to count

K1 is a cell with the fill colour you want to count.

Function Countcolour(rng As Range, colour As Range) As Long

Dim c as Range

Application.Volatile

For Each c In rng

    If c.Interior.ColorIndex = colour.Interior.ColorIndex Then

        Countcolour = Countcolour + 1

    End If

Next

End Function


If this post answers your question, please mark it as the Answer.

Mike H

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Anonymous
2010-11-01T12:34:16+00:00

To expand on HansV (and MikeH's) comments... You might consider using the same criteria that you used to set the colors to count them.  If you used conditional formatting to color them, then use the same criteria to get a count of them using either SUMPRODUCT() [works for all versions of Excel], or COUNTIFS() [Excel 2007 & later only] to get a count.

Here are 3 example formulas assuming a list of integers in cells from A2:A7 that you want to count the cells in that are:

  1. greater than zero, but less than 11 (i.e. 1-10) (perhaps your RED cells)
  2. greater than 10, but less than 21 (i.e. 11-20) (perhaps your YELLOW cells)
  3. greater than 20, but less than 31 (i.e. 21-30) (perhaps your GREEN cells)

Using SUMPRODUCT():

=SUMPRODUCT(--(A2:A7>0),--(A2:A7<11))

=SUMPRODUCT(--(A2:A7>10),--(A2:A7<21))

=SUMPRODUCT(--(A2:A7>20),--(A2:A7<31))

Equivalent using SUMIFS()

=COUNTIFS(A2:A7,">0",A2:A7,"<11")

=COUNTIFS(A2:A7,">10",A2:A7,"<21")

=COUNTIFS(A2:A7,">20",A2:A7,"<31")


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  1. Anonymous
    2016-02-09T18:21:28+00:00

    Thank you Mike H.  This was my solution!

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  2. Anonymous
    2016-01-17T22:30:39+00:00

    Mike, many thanks for this.  Works like a charm, saved me 30 minutes trying to find the values for the .colorcode VBA parameter.

    My only complaint is that you misspelled "color." :)

    Best,

    Tony Lima

    Silicon Valley, CA

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  3. Anonymous
    2016-01-14T14:56:39+00:00

    That code didn't compile on my system (mac excel 2015)  but this did:

    Public Function CountColour(CheckValues As Range, CompareColour As Range) As Long

        For Each r In CheckValues

            If r.Interior.Color = CompareColour.Interior.Color Then NumColours = NumColours + 1

        Next

        CountColour = NumColours

    End Function

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