Is there a stop to Internet Backgammon cheaters?

I have many times suffered from the cheat bug wherby opponent moves piece back and forward a few times, and then I don't get a chance to throw before I am timed out.

Does anyone know how this happens, and can it be avoided?

I recorded the first roll of my opponent for 2221 games.  The opponents rolled a 6  861 times or 39% of the time.

The probability of rolling a 6 is 16.7%

The dice are not random or some opponents have control of their roll.

And, yes, there is a way to stop cheaters - don't play them. 

Here's my way of telling a potential cheat (play experts and make them roll first):

1. Their come out roll is a 6 or you have equal rolls and must roll again.
2. Their first free (2 dice) roll is a double or a 65.
3. There is a long pause before their roll.  (They are busy recording moves)
4. There is a long pause after their roll and especially before an obvious move like a 31, 61, 55, etc.
5. They double before their first foll.  (A win is insured for them)
6. When losing severly, they roll 2 life-saving doubles in a row.

The down side is that you will be playing only about 10-20% of the games to the end, win or lose.  It is very difficult to find a non-cheater based on the above.  But, almost guarenteed, if you play them, you will lose.  So why bother.

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New study results.  This time I counted (using a program I developed) their come out roll of a 6 or equal rolls.

The expected probability is 33% (1/6 + 1/6)

I got 242/344 or 70%

---

One more thing...try playing as a beginner, not an expert.  They tend not to use the cheat programs against beginners.

 

The odds of rolling a 6 is not 6 to 1, it is 3 to 1, ie: 33%. This the the same with any number.

 

Many people mistakingly say that the odds of any particular throw is 36 to 1, wheras it is in fact 21 to 1

You are showing you ignorance.  I dare you to roll one die 1000 time and get around 333 sizes!  If you do, then the die is loaded!  I guaranty that you will get close to 166.

Look again, I said the first roll which is ONE die.

I ran this program in BASIC 3 times and out of 1 million rolls got 166,462, 166,596, 166,445 respectively.

randomize

let tot = 0

for i=1 to 1000000

   if int(6*rnd)+1 = 6 then  ! rolled a 6

      let tot = tot + 1

   end if

next i

print tot  !  will be around 166000

end

Read a book!  Then come back to this forum.

I recorded the first roll of my opponent for 2221 games.  The opponents rolled a 6  861 times or 39% of the time.

The probability of rolling a 6 is 16.7%

The dice are not random or some opponents have control of their roll.

And, yes, there is a way to stop cheaters - don't play them. 

Here's my way of telling a potential cheat (play experts and make them roll first):

1. Their come out roll is a 6 or you have equal rolls and must roll again.
2. Their first free (2 dice) roll is a double or a 65.
3. There is a long pause before their roll.  (They are busy recording moves)
4. There is a long pause after their roll and especially before an obvious move like a 31, 61, 55, etc.
5. They double before their first foll.  (A win is insured for them)
6. When losing severly, they roll 2 life-saving doubles in a row.

The down side is that you will be playing only about 10-20% of the games to the end, win or lose.  It is very difficult to find a non-cheater based on the above.  But, almost guarenteed, if you play them, you will lose.  So why bother.

---

New study results.  This time I counted (using a program I developed) their come out roll of a 6 or equal rolls.

The expected probability is 33% (1/6 + 1/6)

I got 242/344 or 70%

---

One more thing...try playing as a beginner, not an expert.  They tend not to use the cheat programs against beginners.

 

The odds of rolling a 6 is not 6 to 1, it is 3 to 1, ie: 33%. This the the same with any number.

Many people mistakingly say that the odds of any particular throw is 36 to 1, wheras it is in fact 21 to 1

There are not 36 different dice combinations, there are 21. there is a 21-1 chance of any given throw